Category: Class 8

Given: \( x + \frac{1}{x} =20 \) To do: We have to find the value of \( x^2 + \frac{1}{x^2}. \) Solution: The given expression is \( x + \frac{1}{x} =20 \). Here, we have to find the value of \( x^2 + \frac{1}{x^2} \). So, by squaring the given expression and using the identity \( (a+b)^2=a^2+2ab+b^2 \), we can find the value of \( x^2 + \frac{1}{x^2}. \) \( (a+b)^2=a^2+2ab+b^2 \)...................(i) Now, \( x + \frac{1}{x} =20 \) Squaring on both sides, we get, \( (x+\frac{1}{x})^2=(20)^2 \) ... Read Mores